Going from 1+1=2 to Quantum Mechanics Chaimongkol, 2026 Observables on a Composite System
Don’t forget that Operator can sometimes be Observable .
Let F ∈ L ( H A ) , G ∈ L ( H B ) F\in L(H_A), G \in L (H_B) F ∈ L ( H A ) , G ∈ L ( H B ) be operators.
Then F ⊗ G ∈ L ( H A ⊗ H B ) F\otimes G \in L(H_A\otimes H_B) F ⊗ G ∈ L ( H A ⊗ H B ) is defined as
( F ⊗ G ) ∣ v , w ⟩ ≜ F ∣ v ⟩ ⊗ G ∣ w ⟩ (F\otimes G)\left\lvert v, w \right\rangle \triangleq F\left\lvert v \right\rangle\otimes G\left\lvert w \right\rangle ( F ⊗ G ) ∣ v , w ⟩ ≜ F ∣ v ⟩ ⊗ G ∣ w ⟩
Upgrading/promoting subsystem operators gets us
F ∈ L ( H A ) → F ⊗ I ∈ L ( H A ⊗ H B ) F\in L(H_A)\rightarrow F\otimes I \in L(H_A\otimes H_B) F ∈ L ( H A ) → F ⊗ I ∈ L ( H A ⊗ H B )
G ∈ L ( H B ) → G ⊗ I ∈ L ( H A ⊗ H B ) G\in L(H_B)\rightarrow G\otimes I \in L(H_A\otimes H_B) G ∈ L ( H B ) → G ⊗ I ∈ L ( H A ⊗ H B )
Where L L L is the Set of all linear operators on a Hilbert space .
This means that any operator acting on a subsystem H A H_A H A can be upgraded to an operator that makes it act on a larger dimension H A ⊗ H B H_A\otimes H_B H A ⊗ H B .
This is because
( F ⊗ I ) ( I ⊗ G ) ∣ v , w ⟩ = ( F ⊗ I ) ( ∣ v ⟩ ⊗ G ∣ w ⟩ ) = F ∣ v ⟩ ⊗ G ∣ w ⟩ (F\otimes I)(I \otimes G)\left\lvert v, w \right\rangle =(F\otimes I)(\left\lvert v \right\rangle\otimes G\left\lvert w \right\rangle) = F\left\lvert v \right\rangle\otimes G\left\lvert w \right\rangle ( F ⊗ I ) ( I ⊗ G ) ∣ v , w ⟩ = ( F ⊗ I ) ( ∣ v ⟩ ⊗ G ∣ w ⟩ ) = F ∣ v ⟩ ⊗ G ∣ w ⟩
Conversely,
( I ⊗ G ) ( F ⊗ I ) ( ∣ v ⟩ ⊗ ∣ w ⟩ ) = F ∣ v ⟩ ⊗ G ∣ w ⟩ (I\otimes G)(F\otimes I)(\left\lvert v \right\rangle\otimes \left\lvert w \right\rangle)=F\left\lvert v \right\rangle\otimes G\left\lvert w \right\rangle ( I ⊗ G ) ( F ⊗ I ) ( ∣ v ⟩ ⊗ ∣ w ⟩ ) = F ∣ v ⟩ ⊗ G ∣ w ⟩
Notation wise, let
F ( A ) ≜ F ⊗ I F^{(A)}\triangleq F\otimes I F ( A ) ≜ F ⊗ I
G ( B ) ≜ I ⊗ G G^{(B)}\triangleq I\otimes G G ( B ) ≜ I ⊗ G
This is form is overloaded, so don’t get confused with notation of states which also can have an superscript ( A ) (A) ( A ) .
Note
[ F ( A ) , G ( B ) ] = [ F ⊗ I , I ⊗ G ] = 0 \boxed{[F^{(A)}, G^{(B)}]= [F\otimes I, I\otimes G]=0} [ F ( A ) , G ( B ) ] = [ F ⊗ I , I ⊗ G ] = 0
For a composite system H = H A ⊗ H B H = H_A \otimes H_B H = H A ⊗ H B , an operators acting only on one subsystem extends to the full space by tensoring with the identity on the other.
Subsystem A A A Subsystem B B B Operator Q ( A ) = Q ⊗ I Q^{(A)} = Q \otimes I Q ( A ) = Q ⊗ I R ( B ) = I ⊗ R R^{(B)} = I \otimes R R ( B ) = I ⊗ R Eigenvalues q a q_a q a r b r_b r b Eigenvectors ∣ a ⟩ \left\lvert a \right\rangle ∣ a ⟩ ∣ b ⟩ \left\lvert b \right\rangle ∣ b ⟩ Index range a = 1 , 2 , … , d A a = 1, 2, \dots, d_A a = 1 , 2 , … , d A b = 1 , 2 , … , d B b = 1, 2, \dots, d_B b = 1 , 2 , … , d B
Sum
Q ( A ) + R ( B ) = Q ⊗ I + I ⊗ R Q^{(A)} + R^{(B)} = Q \otimes I + I \otimes R Q ( A ) + R ( B ) = Q ⊗ I + I ⊗ R
Product
Q ( A ) R ( B ) = Q ⊗ R Q^{(A)} R^{(B)} = Q \otimes R Q ( A ) R ( B ) = Q ⊗ R
Eigenvectors: ∣ a ⟩ ⊗ ∣ b ⟩ \left\lvert a \right\rangle \otimes \left\lvert b \right\rangle ∣ a ⟩ ⊗ ∣ b ⟩
Eigenvalues: q a r b q_a\, r_b q a r b
Singlet