Transpose

We just learned what ket x\left\lvert x \right\rangle means — a N×1N\times 1 vector. Let that ALSO be called a ket. If we flip it horizontally, we get a bra x\left\langle x \right\rvert.

If a ket is

x=(1+3i2+5i7)ψ=(99000)ϕ=(01)\begin{gather*} \left\lvert x \right\rangle=\begin{pmatrix} 1+3i \\ 2+5i \\ 7 \end{pmatrix}\quad \left\lvert \psi \right\rangle=\begin{pmatrix} 9 \\ 9 \\ 0 \\ 0 \\ 0 \end{pmatrix}\quad\left\lvert \phi \right\rangle=\begin{pmatrix} 0 \\ 1 \end{pmatrix} \end{gather*}

Then it’s counterpart is a bra

x=(13i25i7)ψ=(99000)ϕ=(01)\begin{gather*} \left\langle x \right\rvert=\begin{pmatrix} 1-3i & 2-5i & 7 \end{pmatrix}\quad \left\langle \psi \right\rvert=\begin{pmatrix} 9 & 9 & 0 & 0 & 0 \end{pmatrix}\quad\left\langle \phi \right\rvert=\begin{pmatrix} 0 & 1 \end{pmatrix} \end{gather*}

You swap the columns for the rows (transpose!) and make every Element the Conjugate of itself. It becomes a 1×N1\times N matrix instead.

Let this weird transformation be known as a conjugate transpose, denoted as

v=(v)+\begin{gather*} \left\langle v \right\rvert=(\left\lvert v \right\rangle)^+ \end{gather*}